7y+y^2=4544

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Solution for 7y+y^2=4544 equation:



7y+y^2=4544
We move all terms to the left:
7y+y^2-(4544)=0
a = 1; b = 7; c = -4544;
Δ = b2-4ac
Δ = 72-4·1·(-4544)
Δ = 18225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{18225}=135$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-135}{2*1}=\frac{-142}{2} =-71 $
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+135}{2*1}=\frac{128}{2} =64 $

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